√ (x-y)^3=x^3-y^3-3xy(x-y) 175764-(x-y)^(3)=x^(3)-y^(3)-3xy(x-y) =x^(3)-3x^(2)y+3xy^(2)-y^(3)

Tinh Gia Trị Biểu Thức A X 3 3xy X Y Y 3 X 2 2xy Y 2 Khi X Y 7 Cau Hỏi Hoidap247 Com

Giải các bài toán của bạn sử dụng công cụ giải toán miễn phí của chúng tôi với lời giải theo từng bước Công cụ giải toán của chúng tôi hỗ trợ bài toán cơ bản, đại số sơ cấp, đại số, lượng giác, vi tích phân và nhiều hơn nữaCalculus Find dy/dx x^3y^3=3xy^2 x3 y3 = 3xy2 x 3 y 3 = 3 x y 2 Differentiate both sides of the equation d dx (x3 y3) = d dx(3xy2) d d x ( x 3 y 3) = d d x ( 3 x y 2) Differentiate the left side of the equation Tap for more steps

(x-y)^(3)=x^(3)-y^(3)-3xy(x-y) =x^(3)-3x^(2)y+3xy^(2)-y^(3)

(x-y)^(3)=x^(3)-y^(3)-3xy(x-y) =x^(3)-3x^(2)y+3xy^(2)-y^(3)-Answer (1 of 3) x^3 y^3 = 3xy d/dx(x^3 y^3) = d/dx(3xy) 3x^2 3y^2 * dy/dx = 3y 3x * dy/dx 3x^2 3y^2 * dy/dx 3x^2 3x * dy/dx = 3y 3x * dy/dx 3x^2 3x * dy/dx 3y^2 * dy/dx 3x * dy/dx = 3y 3x^2 dy/dx * (3y^2 3x) = (3y 3x^2) dy/dx * (3y^2 3x) / (3y^2 3x) = (3yClick here👆to get an answer to your question ️ If x y = 1 then x^3 y^3 3xy =

Solve X 3 3xy 2 Dx Y 3 3x 2y Dy Sarthaks Econnect Largest Online Education Community

How do you Use implicit differentiation to find the equation of the tangent line to the curve How do you use implicit differentiation to find #y'# for #sin(xy) = 1#?We are told to find the global extrema of the function f(x,y)=x^3y^33xy on the rectangle R=0,2\times{2},2 This R is a stratified set, having an open interior, the relative interiors More Items Share Copy Copied to clipboard Examples Quadratic equation { x } ^ { 2 } 4 x 5 = 0Calculate the area B, described by the curve (x,y > 0) x 3 y 3 − 3 x y = 0 There are many ways to do this but my university told me to transform the curve into r ( t);

Calculus Find dy/dx x^33xyy^3=3 x3 − 3xy y3 = 3 x 3 3 x y y 3 = 3 Differentiate both sides of the equation d dx (x3 −3xy y3) = d dx (3) d d x ( x 3 3 x y y 3) = d d x ( 3) Differentiate the left side of the equation Tap for more steps DifferentiateExperts are tested by Chegg as specialists in their subject area We review their content and use your feedback to keep the quality high Transcribed image text Find y' for y = y (x) defined implicitly by 3xy x^2 4 = 0 y' = 2/3 x y' = 3x 2y/4 y' = 3y 2x/3x y' = 2x 3y/3xSolutionShow Solution Elaborating x 3 y 3 using identity a 3 b 3 = (a b) (a 2 ab b 2 ) = x ( x y) (x 2 xy y 2 ) 3xy (x y ) Taking common x ( x y ) in both the terms = x ( x y) {x 2 xy y 2 3y} ∴ x (x 3 y 3 ) 3xy ( x y) = x ( x y ) (x 2 xy y 2 3y)

(x-y)^(3)=x^(3)-y^(3)-3xy(x-y) =x^(3)-3x^(2)y+3xy^(2)-y^(3)のギャラリー

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Find the extreme values of the function x 3 y 3 – 3xy differential calculus; Explanation y3 x3 = 3xy 3y2 dy dx 3x2 = 3(x dy dx y ⋅ 1) (Inplicit differentiation, Power rule and Product rule) 3(y2 −x) dy dx = 3(y − x2) Multiply through by ( − 1 3) → (x −y2) dy dx = (x2 − y) dy dx = x2 −y x −y2 Answer link

Incoming Term: (x+y)^3=x^3+y^3+3xy(x+y), x(x^3-y^3)+3xy(x-y) solution, x^3/x^3-3x^2y+3xy^2-y^3 x/y^2-xy, (x-y)^(3)=x^(3)-y^(3)-3xy(x-y) =x^(3)-3x^(2)y+3xy^(2)-y^(3), x^3+y^3-2x^2-2y^2+3xy(x+y)-4xy+3(x+y)+10, (x+y)3=x3+y3+3xy(x+y),

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